What is the general solution for cos(2θ)-cos^2(θ)=0 ?

The general solution for cos(2θ)-cos^2(θ)=0 is θ=2pin,θ=pi+2pin

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cos(2θ)-cos^2(θ)=0

cos (2 θ) - cos^{2} (θ) = 0

θ = 2 πn, θ = π + 2 πn

Solution steps

cos (2 θ) - cos^{2} (θ) = 0

Rewrite using trig identities

- sin^{2} (θ) = 0

Divide both sides by

- 1

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

3 tan^{2} (x) + 5 tan (x) - 4 = 0

cos (2 x) \cdot 2 = 0

csc^{3} (x) + csc^{2} (x) = 4 csc (x) + 4

2 sin^{2} (x) - 5 sin (x) - 3 = 0

6 + 6 sin (θ) = 4 cos^{2} (θ)

What is the general solution for cos(2θ)-cos^2(θ)=0 ?
The general solution for cos(2θ)-cos^2(θ)=0 is θ=2pin,θ=pi+2pin