What is the general solution for cos^2(x)+2cos(x)-2=0 ?

The general solution for cos^2(x)+2cos(x)-2=0 is x=0.74946…+2pin,x=2pi-0.74946…+2pin

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cos^2(x)+2cos(x)-2=0

cos^{2} (x) + 2 cos (x) - 2 = 0

x = 0.74946 \dots + 2 πn, x = 2 π - 0.74946 \dots + 2 πn

Solution steps

cos^{2} (x) + 2 cos (x) - 2 = 0

Solve by substitution

cos (x) = - 1 + 3, cos (x) = - 1 - 3

cos (x) = - 1 + 3 : x = arccos (- 1 + 3) + 2 πn, x = 2 π - arccos (- 1 + 3) + 2 πn

cos (x) = - 1 - 3 :

No Solution

Combine all the solutions

x = arccos (- 1 + 3) + 2 πn, x = 2 π - arccos (- 1 + 3) + 2 πn

Show solutions in decimal form

x = 0.74946 \dots + 2 πn, x = 2 π - 0.74946 \dots + 2 πn

- sin (4 x) \cdot 4 = 0

cos (θ) = \frac{5}{6}

cos (2 x) = cos^{2} (x) - \frac{1}{2}

cos (x) = 1, 0 \leq x \leq 2 π

x, cot (- x) cos (- x) + sin (- x) = \frac{- 1}{f}

What is the general solution for cos^2(x)+2cos(x)-2=0 ?
The general solution for cos^2(x)+2cos(x)-2=0 is x=0.74946…+2pin,x=2pi-0.74946…+2pin