What is the general solution for cos(2x-pi/4)=(sqrt(2))/2 ?

The general solution for cos(2x-pi/4)=(sqrt(2))/2 is x= pi/4+pin,x=pin+pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(2x-pi/4)=(sqrt(2))/2

Solution

cos (2 x - \frac{π}{4}) = \frac{2}{2}

Solution

x = \frac{π}{4} + πn, x = πn + π

Degrees

x = 4 5^{\circ} + 18 0^{\circ} n, x = 18 0^{\circ} + 18 0^{\circ} n

Solution steps

cos (2 x - \frac{π}{4}) = \frac{2}{2}

General solutions for

cos (2 x - \frac{π}{4}) = \frac{2}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

2 x - \frac{π}{4} = \frac{π}{4} + 2 πn, 2 x - \frac{π}{4} = \frac{7 π}{4} + 2 πn

2 x - \frac{π}{4} = \frac{π}{4} + 2 πn, 2 x - \frac{π}{4} = \frac{7 π}{4} + 2 πn

Solve

2 x - \frac{π}{4} = \frac{π}{4} + 2 πn : x = \frac{π}{4} + πn

2 x - \frac{π}{4} = \frac{π}{4} + 2 πn

Move

\frac{π}{4}

to the right side

2 x - \frac{π}{4} = \frac{π}{4} + 2 πn

Add

\frac{π}{4}

to both sides

2 x - \frac{π}{4} + \frac{π}{4} = \frac{π}{4} + 2 πn + \frac{π}{4}

Simplify

2 x - \frac{π}{4} + \frac{π}{4} = \frac{π}{4} + 2 πn + \frac{π}{4}

Simplify

2 x - \frac{π}{4} + \frac{π}{4} : 2 x

2 x - \frac{π}{4} + \frac{π}{4}

Add similar elements:

- \frac{π}{4} + \frac{π}{4} = 0

= 2 x

Simplify

\frac{π}{4} + 2 πn + \frac{π}{4} : \frac{π}{2} + 2 πn

\frac{π}{4} + 2 πn + \frac{π}{4}

Group like terms

= \frac{π}{4} + \frac{π}{4} + 2 πn

Combine the fractions

\frac{π}{4} + \frac{π}{4} : \frac{π}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π + π}{4}

Add similar elements:

π + π = 2 π

= \frac{2 π}{4}

Cancel the common factor:

2

= \frac{π}{2}

= \frac{π}{2} + 2 πn

2 x = \frac{π}{2} + 2 πn

2 x = \frac{π}{2} + 2 πn

2 x = \frac{π}{2} + 2 πn

Divide both sides by

2

2 x = \frac{π}{2} + 2 πn

Divide both sides by

2

\frac{2 x}{2} = \frac{\frac{π}{2}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} = \frac{\frac{π}{2}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{\frac{π}{2}}{2} + \frac{2 πn}{2} : \frac{π}{4} + πn

\frac{\frac{π}{2}}{2} + \frac{2 πn}{2}

\frac{\frac{π}{2}}{2} = \frac{π}{4}

\frac{\frac{π}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{π}{4}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

= \frac{π}{4} + πn

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

Solve

2 x - \frac{π}{4} = \frac{7 π}{4} + 2 πn : x = πn + π

2 x - \frac{π}{4} = \frac{7 π}{4} + 2 πn

Move

\frac{π}{4}

to the right side

2 x - \frac{π}{4} = \frac{7 π}{4} + 2 πn

Add

\frac{π}{4}

to both sides

2 x - \frac{π}{4} + \frac{π}{4} = \frac{7 π}{4} + 2 πn + \frac{π}{4}

Simplify

2 x - \frac{π}{4} + \frac{π}{4} = \frac{7 π}{4} + 2 πn + \frac{π}{4}

Simplify

2 x - \frac{π}{4} + \frac{π}{4} : 2 x

2 x - \frac{π}{4} + \frac{π}{4}

Add similar elements:

- \frac{π}{4} + \frac{π}{4} = 0

= 2 x

Simplify

\frac{7 π}{4} + 2 πn + \frac{π}{4} : 2 πn + 2 π

\frac{7 π}{4} + 2 πn + \frac{π}{4}

Group like terms

= 2 πn + \frac{π}{4} + \frac{7 π}{4}

Combine the fractions

\frac{π}{4} + \frac{7 π}{4} : 2 π

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π + 7 π}{4}

Add similar elements:

π + 7 π = 8 π

= \frac{8 π}{4}

Divide the numbers:

\frac{8}{4} = 2

= 2 π

= 2 πn + 2 π

2 x = 2 πn + 2 π

2 x = 2 πn + 2 π

2 x = 2 πn + 2 π

Divide both sides by

2

2 x = 2 πn + 2 π

Divide both sides by

2

\frac{2 x}{2} = \frac{2 πn}{2} + \frac{2 π}{2}

Simplify

x = πn + π

x = πn + π

x = \frac{π}{4} + πn, x = πn + π

Popular Examples

sin(5t)-1=0

sin (5 t) - 1 = 0

2sin(θ)cos(θ)-sin(θ)=0

2 sin (θ) cos (θ) - sin (θ) = 0

9sin(x)tan(x)-2tan(x)=0

9 sin (x) tan (x) - 2 tan (x) = 0

sqrt(3)cot(3x)+1=0

3 cot (3 x) + 1 = 0

tan(4x)=sqrt(3)

tan (4 x) = 3

Frequently Asked Questions (FAQ)

What is the general solution for cos(2x-pi/4)=(sqrt(2))/2 ?
The general solution for cos(2x-pi/4)=(sqrt(2))/2 is x= pi/4+pin,x=pin+pi