What is the general solution for 5tan^2(x)-15=0 ?

The general solution for 5tan^2(x)-15=0 is x= pi/3+pin,x=(2pi)/3+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5tan^2(x)-15=0

5 tan^{2} (x) - 15 = 0

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

Solution steps

5 tan^{2} (x) - 15 = 0

Solve by substitution

tan (x) = 3, tan (x) = - 3

tan (x) = 3 : x = \frac{π}{3} + πn

tan (x) = - 3 : x = \frac{2 π}{3} + πn

Combine all the solutions

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

- 2 cos^{2} (x) = - cos (x) - 1

sin (θ) = - \frac{2}{5}

- sin^{2} (x) = 2 cos (x) - 2

3 sin (2 θ) - 5 sin (θ) = 0

cos (2 x) = cos (x), 0 \leq x \leq 2 π

What is the general solution for 5tan^2(x)-15=0 ?
The general solution for 5tan^2(x)-15=0 is x= pi/3+pin,x=(2pi)/3+pin