What is the general solution for -sqrt(3)tan(θ)-6=-3 ?

The general solution for -sqrt(3)tan(θ)-6=-3 is θ=(2pi)/3+pin

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-sqrt(3)tan(θ)-6=-3

- 3 tan (θ) - 6 = - 3

θ = \frac{2 π}{3} + πn

Solution steps

- 3 tan (θ) - 6 = - 3

Move

6

to the right side

- 3 tan (θ) = 3

Divide both sides by

- 3

tan (θ) = - 3

General solutions for

tan (θ) = - 3

θ = \frac{2 π}{3} + πn

tan (θ) = 2.5

arccos (1 - x) + arccos (x) = arccos (- x)

tan (x) = 0.75

2 sin (x) tan (x) = tan (x)

4 csc (θ) + 5 = 0

What is the general solution for -sqrt(3)tan(θ)-6=-3 ?
The general solution for -sqrt(3)tan(θ)-6=-3 is θ=(2pi)/3+pin