What is the general solution for cos(2x)-cos^2(x)=0 ?

The general solution for cos(2x)-cos^2(x)=0 is x=2pin,x=pi+2pin

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cos(2x)-cos^2(x)=0

cos (2 x) - cos^{2} (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

cos (2 x) - cos^{2} (x) = 0

Rewrite using trig identities

- sin^{2} (x) = 0

Divide both sides by

- 1

sin (x) = 0

General solutions for

sin (x) = 0

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn, x = π + 2 πn

tan (π - θ) = tan (θ)

8 cos (x) = sec^{2} (x)

5 cot (θ) - 4 = 0

5 (sin (x) + 1) = 5

2 sin^{2} (t) - 3 cos (t) = 3

What is the general solution for cos(2x)-cos^2(x)=0 ?
The general solution for cos(2x)-cos^2(x)=0 is x=2pin,x=pi+2pin