What is the general solution for 5cot(θ)-4=0 ?

The general solution for 5cot(θ)-4=0 is θ=0.89605…+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5cot(θ)-4=0

5 cot (θ) - 4 = 0

θ = 0.89605 \dots + πn

Degrees

θ = 51.34019 \dots^{\circ} + 18 0^{\circ} n

Solution steps

5 cot (θ) - 4 = 0

Move

4

to the right side

5 cot (θ) - 4 = 0

Add

4

to both sides

5 cot (θ) - 4 + 4 = 0 + 4

Simplify

5 cot (θ) = 4

5 cot (θ) = 4

Divide both sides by

5

5 cot (θ) = 4

Divide both sides by

5

\frac{5 cot ( θ )}{5} = \frac{4}{5}

Simplify

cot (θ) = \frac{4}{5}

cot (θ) = \frac{4}{5}

Apply trig inverse properties

cot (θ) = \frac{4}{5}

General solutions for

cot (θ) = \frac{4}{5}

cot (x) = a \Rightarrow x = arccot (a) + πn

θ = arccot (\frac{4}{5}) + πn

θ = arccot (\frac{4}{5}) + πn

Show solutions in decimal form

θ = 0.89605 \dots + πn

5 (sin (x) + 1) = 5

2 sin^{2} (t) - 3 cos (t) = 3

cos (x) = \frac{3}{2}, 0 \leq x \leq 2 π

csc^{2} (x) + 4 csc (x) + 4 = 0

6 sin^{2} (x) - cos (x) - 4 = 0

What is the general solution for 5cot(θ)-4=0 ?
The general solution for 5cot(θ)-4=0 is θ=0.89605…+pin