What is the general solution for 5cot(θ)-4=0 ?

The general solution for 5cot(θ)-4=0 is θ=0.89605…+pin

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5cot(θ)-4=0

5 cot (θ) - 4 = 0

θ = 0.89605 \dots + πn

Solution steps

5 cot (θ) - 4 = 0

Move

4

to the right side

5 cot (θ) = 4

Divide both sides by

5

cot (θ) = \frac{4}{5}

Apply trig inverse properties

θ = arccot (\frac{4}{5}) + πn

Show solutions in decimal form

θ = 0.89605 \dots + πn

5 (sin (x) + 1) = 5

2 sin^{2} (t) - 3 cos (t) = 3

cos (x) = \frac{3}{2}, 0 \leq x \leq 2 π

csc^{2} (x) + 4 csc (x) + 4 = 0

6 sin^{2} (x) - cos (x) - 4 = 0

What is the general solution for 5cot(θ)-4=0 ?
The general solution for 5cot(θ)-4=0 is θ=0.89605…+pin