What is the general solution for cos(x)=(sqrt(3))/2 ,0<= x<= 2pi ?

The general solution for cos(x)=(sqrt(3))/2 ,0<= x<= 2pi is x= pi/6 ,x=(11pi)/6

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cos(x)=(sqrt(3))/2 ,0<= x<= 2pi

cos (x) = \frac{3}{2}, 0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{11 π}{6}

Degrees

x = 3 0^{\circ}, x = 33 0^{\circ}

Solution steps

cos (x) = \frac{3}{2}, 0 \leq x \leq 2 π

General solutions for

cos (x) = \frac{3}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{11 π}{6}

csc^{2} (x) + 4 csc (x) + 4 = 0

6 sin^{2} (x) - cos (x) - 4 = 0

2 sin (2 x) cos (x) + sin (x) = 0

4 cos (x) + 1 = 3

y, x = sin (y)

What is the general solution for cos(x)=(sqrt(3))/2 ,0<= x<= 2pi ?
The general solution for cos(x)=(sqrt(3))/2 ,0<= x<= 2pi is x= pi/6 ,x=(11pi)/6