What is the general solution for sin(x)+2=3,0<x<360 ?

The general solution for sin(x)+2=3,0<x<360 is x=90

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sin(x)+2=3,0<x<360

sin (x) + 2 = 3, 0^{\circ} < x < 36 0^{\circ}

x = 9 0^{\circ}

Solution steps

sin (x) + 2 = 3, 0^{\circ} < x < 36 0^{\circ}

Move

2

to the right side

sin (x) = 1

General solutions for

sin (x) = 1

x = 9 0^{\circ} + 36 0^{\circ} n

Solutions for the range

0 < x < 36 0^{\circ}

x = 9 0^{\circ}

cos (\frac{2 x}{3}) = 0

sin (2 x) - 1 = cos (2 x)

- 2 sin (t) + 2 cos (2 t) = 0

sin (2 x) = sin (x), 0 \leq x \leq 2 π

sin (5 θ) = \frac{1}{2}

What is the general solution for sin(x)+2=3,0<x<360 ?
The general solution for sin(x)+2=3,0<x<360 is x=90