What is the general solution for sin(5θ)= 1/2 ?

The general solution for sin(5θ)= 1/2 is θ= pi/(30)+(2pin)/5 ,θ= pi/6+(2pin)/5

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sin(5θ)= 1/2

sin (5 θ) = \frac{1}{2}

θ = \frac{π}{30} + \frac{2 πn}{5}, θ = \frac{π}{6} + \frac{2 πn}{5}

Solution steps

sin (5 θ) = \frac{1}{2}

General solutions for

sin (5 θ) = \frac{1}{2}

5 θ = \frac{π}{6} + 2 πn, 5 θ = \frac{5 π}{6} + 2 πn

Solve

5 θ = \frac{π}{6} + 2 πn : θ = \frac{π}{30} + \frac{2 πn}{5}

Solve

5 θ = \frac{5 π}{6} + 2 πn : θ = \frac{π}{6} + \frac{2 πn}{5}

θ = \frac{π}{30} + \frac{2 πn}{5}, θ = \frac{π}{6} + \frac{2 πn}{5}

tan (θ) - 5 = 4 tan (θ) - 5

3 tan^{2} (x) - 3 = 0

2 sin (θ) = cos (θ)

2 cos (x) = - 1

2 sec (u) sin (u) + 2 = 4 sin (u) + sec (u)

What is the general solution for sin(5θ)= 1/2 ?
The general solution for sin(5θ)= 1/2 is θ= pi/(30)+(2pin)/5 ,θ= pi/6+(2pin)/5