What is the general solution for cos(4θ)=0 ?

The general solution for cos(4θ)=0 is θ= pi/8+(pin)/2 ,θ=(3pi)/8+(pin)/2

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cos(4θ)=0

cos (4 θ) = 0

θ = \frac{π}{8} + \frac{πn}{2}, θ = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

cos (4 θ) = 0

General solutions for

cos (4 θ) = 0

4 θ = \frac{π}{2} + 2 πn, 4 θ = \frac{3 π}{2} + 2 πn

Solve

4 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{8} + \frac{πn}{2}

Solve

4 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{8} + \frac{πn}{2}

θ = \frac{π}{8} + \frac{πn}{2}, θ = \frac{3 π}{8} + \frac{πn}{2}

t, L {sin (2 t)} = \frac{2}{s ^{2} + 4}

2 sec^{2} (x) + tan (x) = 5

1 - sin (x) = cos (2 x)

sin (x) - \frac{1}{2} = 0

4 cos^{2} (x) = 3 - 4 cos (x)

What is the general solution for cos(4θ)=0 ?
The general solution for cos(4θ)=0 is θ= pi/8+(pin)/2 ,θ=(3pi)/8+(pin)/2