What is the general solution for -2cos(b)+4=cos(b)+6 ?

The general solution for -2cos(b)+4=cos(b)+6 is b=2.30052…+2pin,b=-2.30052…+2pin

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-2cos(b)+4=cos(b)+6

- 2 cos (b) + 4 = cos (b) + 6

b = 2.30052 \dots + 2 πn, b = - 2.30052 \dots + 2 πn

Solution steps

- 2 cos (b) + 4 = cos (b) + 6

Solve by substitution

cos (b) = - \frac{2}{3}

cos (b) = - \frac{2}{3} : b = arccos (- \frac{2}{3}) + 2 πn, b = - arccos (- \frac{2}{3}) + 2 πn

Combine all the solutions

b = arccos (- \frac{2}{3}) + 2 πn, b = - arccos (- \frac{2}{3}) + 2 πn

Show solutions in decimal form

b = 2.30052 \dots + 2 πn, b = - 2.30052 \dots + 2 πn

25 csc^{2} (θ) - 4 = 0

tan (θ) = \frac{1}{5}

3 cos (2 x) = 2

3 cos (2 x) = 0

3 cos (x) - 3 sin (x) = 0

What is the general solution for -2cos(b)+4=cos(b)+6 ?
The general solution for -2cos(b)+4=cos(b)+6 is b=2.30052…+2pin,b=-2.30052…+2pin