What is the general solution for cos(-θ)=-cos(θ) ?

The general solution for cos(-θ)=-cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin

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cos(-θ)=-cos(θ)

cos (- θ) = - cos (θ)

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

cos (- θ) = - cos (θ)

Rewrite using trig identities

cos (θ) = - cos (θ)

Subtract

- cos (θ)

from both sides

2 cos (θ) = 0

Divide both sides by

2

cos (θ) = 0

General solutions for

cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

sin^{2} (x) cos (x) = cos (x)

sin (x) = \frac{1}{cos ( x )}

tan (x) + 3 cot (x) = 5 sec (x)

6 sin (θ) + 3 = 0

2 cos (x) + sin (2 x) = 0

What is the general solution for cos(-θ)=-cos(θ) ?
The general solution for cos(-θ)=-cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin