What is the general solution for sin^2(θ)-cos^2(θ)=1 ?

The general solution for sin^2(θ)-cos^2(θ)=1 is θ= pi/2+pin

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sin^2(θ)-cos^2(θ)=1

sin^{2} (θ) - cos^{2} (θ) = 1

θ = \frac{π}{2} + πn

Solution steps

sin^{2} (θ) - cos^{2} (θ) = 1

Rewrite using trig identities

- cos (2 θ) = 1

Divide both sides by

- 1

cos (2 θ) = - 1

General solutions for

cos (2 θ) = - 1

2 θ = π + 2 πn

Solve

2 θ = π + 2 πn : θ = \frac{π}{2} + πn

θ = \frac{π}{2} + πn

2 sin (3 θ) = 2

cot^{2} (x) + 2 cot (x) + 1 = 0

(cot (x) + 1) (3 cot (x) + 1) = 0

3 sin (θ) = - cos (θ)

- 2 sin (x) + 1 = 0

What is the general solution for sin^2(θ)-cos^2(θ)=1 ?
The general solution for sin^2(θ)-cos^2(θ)=1 is θ= pi/2+pin