What is the general solution for 1=2sin(x) ?

The general solution for 1=2sin(x) is x= pi/6+2pin,x=(5pi)/6+2pin

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1=2sin(x)

1 = 2 sin (x)

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

1 = 2 sin (x)

Switch sides

2 sin (x) = 1

Divide both sides by

2

sin (x) = \frac{1}{2}

General solutions for

sin (x) = \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

\frac{cos ( x )}{sin ( x )} = cos^{2} (x)

sin (2 x - \frac{π}{4}) = 0

7 sin^{2} (θ) - 4 sin (θ) = 3

tan (θ) - cot (θ) = 0

csc^{3} (x) + csc^{2} (x) = \frac{4}{3} csc (x) + \frac{4}{3}

What is the general solution for 1=2sin(x) ?
The general solution for 1=2sin(x) is x= pi/6+2pin,x=(5pi)/6+2pin