What is the general solution for sin(θ/2)=(sqrt(2))/2 ?

The general solution for sin(θ/2)=(sqrt(2))/2 is θ= pi/2+4pin,θ=(3pi)/2+4pin

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sin(θ/2)=(sqrt(2))/2

sin (\frac{θ}{2}) = \frac{2}{2}

θ = \frac{π}{2} + 4 πn, θ = \frac{3 π}{2} + 4 πn

Solution steps

sin (\frac{θ}{2}) = \frac{2}{2}

General solutions for

sin (\frac{θ}{2}) = \frac{2}{2}

\frac{θ}{2} = \frac{π}{4} + 2 πn, \frac{θ}{2} = \frac{3 π}{4} + 2 πn

Solve

\frac{θ}{2} = \frac{π}{4} + 2 πn : θ = \frac{π}{2} + 4 πn

Solve

\frac{θ}{2} = \frac{3 π}{4} + 2 πn : θ = \frac{3 π}{2} + 4 πn

θ = \frac{π}{2} + 4 πn, θ = \frac{3 π}{2} + 4 πn

9 tan (3 x) = 9

sin (θ) = \frac{40}{41}

cos (2 x) - sin^{2} (x) = \frac{1}{4}

sec (θ) csc (θ) + 2 csc (θ) = 0

2 sin^{2} (θ) - sin (θ) - 1 = 0, 0 \leq θ \leq 2 π

What is the general solution for sin(θ/2)=(sqrt(2))/2 ?
The general solution for sin(θ/2)=(sqrt(2))/2 is θ= pi/2+4pin,θ=(3pi)/2+4pin