What is the general solution for sin(θ)= 40/41 ?

The general solution for sin(θ)= 40/41 is θ=1.34948…+2pin,θ=pi-1.34948…+2pin

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sin(θ)= 40/41

sin (θ) = \frac{40}{41}

θ = 1.34948 \dots + 2 πn, θ = π - 1.34948 \dots + 2 πn

Solution steps

sin (θ) = \frac{40}{41}

Apply trig inverse properties

θ = arcsin (\frac{40}{41}) + 2 πn, θ = π - arcsin (\frac{40}{41}) + 2 πn

Show solutions in decimal form

θ = 1.34948 \dots + 2 πn, θ = π - 1.34948 \dots + 2 πn

cos (2 x) - sin^{2} (x) = \frac{1}{4}

sec (θ) csc (θ) + 2 csc (θ) = 0

2 sin^{2} (θ) - sin (θ) - 1 = 0, 0 \leq θ \leq 2 π

sin (3 θ) = \frac{2}{2}

(tan^{2} (θ) - 9) (2 cos (θ) + 1) = 0

What is the general solution for sin(θ)= 40/41 ?
The general solution for sin(θ)= 40/41 is θ=1.34948…+2pin,θ=pi-1.34948…+2pin