What is the general solution for 8sin(θ)-8=4sqrt(3)-8 ?

The general solution for 8sin(θ)-8=4sqrt(3)-8 is θ= pi/3+2pin,θ=(2pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8sin(θ)-8=4sqrt(3)-8

8 sin (θ) - 8 = 43 - 8

θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn

Solution steps

8 sin (θ) - 8 = 43 - 8

Add

8

to both sides

8 sin (θ) - 8 + 8 = 43 - 8 + 8

Simplify

8 sin (θ) = 43

Divide both sides by

8

sin (θ) = \frac{3}{2}

General solutions for

sin (θ) = \frac{3}{2}

θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn

sec (θ) = 2 cos (θ)

2 sin^{2} (x) + 3 sin (x) = 0

sin^{2} (x) = - sin (x)

arccos (x) + 2 arcsin (\frac{3}{2}) = π

3 - 3 sin (θ) = 2 cos^{2} (θ)

What is the general solution for 8sin(θ)-8=4sqrt(3)-8 ?
The general solution for 8sin(θ)-8=4sqrt(3)-8 is θ= pi/3+2pin,θ=(2pi)/3+2pin