What is the general solution for arccos(x)+2arcsin((sqrt(3))/2)=pi ?

The general solution for arccos(x)+2arcsin((sqrt(3))/2)=pi is x= 1/2

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arccos(x)+2arcsin((sqrt(3))/2)=pi

arccos (x) + 2 arcsin (\frac{3}{2}) = π

x = \frac{1}{2}

Solution steps

arccos (x) + 2 arcsin (\frac{3}{2}) = π

arcsin (\frac{3}{2}) = \frac{π}{3}

arccos (x) + 2 \cdot \frac{π}{3} = π

Move

2 \frac{π}{3}

to the right side

arccos (x) = π - \frac{2 π}{3}

Apply trig inverse properties

x = \frac{1}{2}

3 - 3 sin (θ) = 2 cos^{2} (θ)

tan (a) = - 3

cos^{2} (θ) = sin^{2} (θ)

csc (t) = \frac{1}{4}

sin (θ) = 0.21

What is the general solution for arccos(x)+2arcsin((sqrt(3))/2)=pi ?
The general solution for arccos(x)+2arcsin((sqrt(3))/2)=pi is x= 1/2