What is the general solution for 2cos(2x-pi/2)=sqrt(3) ?

The general solution for 2cos(2x-pi/2)=sqrt(3) is x=pin+pi/3 ,x=pin+(7pi)/6

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2cos(2x-pi/2)=sqrt(3)

Solution

2 cos (2 x - \frac{π}{2}) = 3

Solution

x = πn + \frac{π}{3}, x = πn + \frac{7 π}{6}

Degrees

x = 6 0^{\circ} + 18 0^{\circ} n, x = 21 0^{\circ} + 18 0^{\circ} n

Solution steps

2 cos (2 x - \frac{π}{2}) = 3

Divide both sides by

2

2 cos (2 x - \frac{π}{2}) = 3

Divide both sides by

2

\frac{2 cos ( 2 x - \frac{π}{2} )}{2} = \frac{3}{2}

Simplify

cos (2 x - \frac{π}{2}) = \frac{3}{2}

cos (2 x - \frac{π}{2}) = \frac{3}{2}

General solutions for

cos (2 x - \frac{π}{2}) = \frac{3}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

2 x - \frac{π}{2} = \frac{π}{6} + 2 πn, 2 x - \frac{π}{2} = \frac{11 π}{6} + 2 πn

2 x - \frac{π}{2} = \frac{π}{6} + 2 πn, 2 x - \frac{π}{2} = \frac{11 π}{6} + 2 πn

Solve

2 x - \frac{π}{2} = \frac{π}{6} + 2 πn : x = πn + \frac{π}{3}

2 x - \frac{π}{2} = \frac{π}{6} + 2 πn

Move

\frac{π}{2}

to the right side

2 x - \frac{π}{2} = \frac{π}{6} + 2 πn

Add

\frac{π}{2}

to both sides

2 x - \frac{π}{2} + \frac{π}{2} = \frac{π}{6} + 2 πn + \frac{π}{2}

Simplify

2 x - \frac{π}{2} + \frac{π}{2} = \frac{π}{6} + 2 πn + \frac{π}{2}

Simplify

2 x - \frac{π}{2} + \frac{π}{2} : 2 x

2 x - \frac{π}{2} + \frac{π}{2}

Add similar elements:

- \frac{π}{2} + \frac{π}{2} = 0

= 2 x

Simplify

\frac{π}{6} + 2 πn + \frac{π}{2} : 2 πn + \frac{2 π}{3}

\frac{π}{6} + 2 πn + \frac{π}{2}

Group like terms

= 2 πn + \frac{π}{6} + \frac{π}{2}

Least Common Multiplier of

6, 2 : 6

6, 2

Least Common Multiplier (LCM)

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Multiply each factor the greatest number of times it occurs in either

6

2

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{π}{2} :

multiply the denominator and numerator by

3

\frac{π}{2} = \frac{π 3}{2 \cdot 3} = \frac{π 3}{6}

= \frac{π}{6} + \frac{π 3}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π + π 3}{6}

Add similar elements:

π + 3 π = 4 π

= \frac{4 π}{6}

Cancel the common factor:

2

= 2 πn + \frac{2 π}{3}

2 x = 2 πn + \frac{2 π}{3}

2 x = 2 πn + \frac{2 π}{3}

2 x = 2 πn + \frac{2 π}{3}

Divide both sides by

2

2 x = 2 πn + \frac{2 π}{3}

Divide both sides by

2

\frac{2 x}{2} = \frac{2 πn}{2} + \frac{\frac{2 π}{3}}{2}

Simplify

\frac{2 x}{2} = \frac{2 πn}{2} + \frac{\frac{2 π}{3}}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{2 πn}{2} + \frac{\frac{2 π}{3}}{2} : πn + \frac{π}{3}

\frac{2 πn}{2} + \frac{\frac{2 π}{3}}{2}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

\frac{\frac{2 π}{3}}{2} = \frac{π}{3}

\frac{\frac{2 π}{3}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{2 π}{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{2 π}{6}

Cancel the common factor:

2

= \frac{π}{3}

= πn + \frac{π}{3}

x = πn + \frac{π}{3}

x = πn + \frac{π}{3}

x = πn + \frac{π}{3}

Solve

2 x - \frac{π}{2} = \frac{11 π}{6} + 2 πn : x = πn + \frac{7 π}{6}

2 x - \frac{π}{2} = \frac{11 π}{6} + 2 πn

Move

\frac{π}{2}

to the right side

2 x - \frac{π}{2} = \frac{11 π}{6} + 2 πn

Add

\frac{π}{2}

to both sides

2 x - \frac{π}{2} + \frac{π}{2} = \frac{11 π}{6} + 2 πn + \frac{π}{2}

Simplify

2 x - \frac{π}{2} + \frac{π}{2} = \frac{11 π}{6} + 2 πn + \frac{π}{2}

Simplify

2 x - \frac{π}{2} + \frac{π}{2} : 2 x

2 x - \frac{π}{2} + \frac{π}{2}

Add similar elements:

- \frac{π}{2} + \frac{π}{2} = 0

= 2 x

Simplify

\frac{11 π}{6} + 2 πn + \frac{π}{2} : 2 πn + \frac{7 π}{3}

\frac{11 π}{6} + 2 πn + \frac{π}{2}

Group like terms

= 2 πn + \frac{π}{2} + \frac{11 π}{6}

Least Common Multiplier of

2, 6 : 6

2, 6

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Multiply each factor the greatest number of times it occurs in either

2

6

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{π}{2} :

multiply the denominator and numerator by

3

\frac{π}{2} = \frac{π 3}{2 \cdot 3} = \frac{π 3}{6}

= \frac{π 3}{6} + \frac{11 π}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π 3 + 11 π}{6}

Add similar elements:

3 π + 11 π = 14 π

= \frac{14 π}{6}

Cancel the common factor:

2

= 2 πn + \frac{7 π}{3}

2 x = 2 πn + \frac{7 π}{3}

2 x = 2 πn + \frac{7 π}{3}

2 x = 2 πn + \frac{7 π}{3}

Divide both sides by

2

2 x = 2 πn + \frac{7 π}{3}

Divide both sides by

2

\frac{2 x}{2} = \frac{2 πn}{2} + \frac{\frac{7 π}{3}}{2}

Simplify

\frac{2 x}{2} = \frac{2 πn}{2} + \frac{\frac{7 π}{3}}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{2 πn}{2} + \frac{\frac{7 π}{3}}{2} : πn + \frac{7 π}{6}

\frac{2 πn}{2} + \frac{\frac{7 π}{3}}{2}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

\frac{\frac{7 π}{3}}{2} = \frac{7 π}{6}

\frac{\frac{7 π}{3}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{7 π}{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{7 π}{6}

= πn + \frac{7 π}{6}

x = πn + \frac{7 π}{6}

x = πn + \frac{7 π}{6}

x = πn + \frac{7 π}{6}

x = πn + \frac{π}{3}, x = πn + \frac{7 π}{6}

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Frequently Asked Questions (FAQ)

What is the general solution for 2cos(2x-pi/2)=sqrt(3) ?
The general solution for 2cos(2x-pi/2)=sqrt(3) is x=pin+pi/3 ,x=pin+(7pi)/6