What is the general solution for 1-cos(2x)=1+cos(2x) ?

The general solution for 1-cos(2x)=1+cos(2x) is x= pi/4+pin,x=(3pi)/4+pin

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1-cos(2x)=1+cos(2x)

1 - cos (2 x) = 1 + cos (2 x)

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

1 - cos (2 x) = 1 + cos (2 x)

Solve by substitution

cos (2 x) = 0

cos (2 x) = 0 : x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

5 cos^{2} (x) - 10 cos (x) + 5 = 0

3 sin (x) - 2 sin (x) cos (x) = 0

8 tan (b) + 12 = 3 tan (b) + 7

sin (θ) + 2 = - sin (θ)

cos (x) = π

What is the general solution for 1-cos(2x)=1+cos(2x) ?
The general solution for 1-cos(2x)=1+cos(2x) is x= pi/4+pin,x=(3pi)/4+pin