What is the general solution for 8tan(b)+12=3tan(b)+7 ?

The general solution for 8tan(b)+12=3tan(b)+7 is b=(3pi)/4+pin

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8tan(b)+12=3tan(b)+7

8 tan (b) + 12 = 3 tan (b) + 7

b = \frac{3 π}{4} + πn

Solution steps

8 tan (b) + 12 = 3 tan (b) + 7

Solve by substitution

tan (b) = - 1

tan (b) = - 1 : b = \frac{3 π}{4} + πn

Combine all the solutions

b = \frac{3 π}{4} + πn

sin (θ) + 2 = - sin (θ)

cos (x) = π

3 cot (θ) + 1 = 0

- cos (x) + sin (x) = 0

cos^{4} (2 x) - sin^{4} (2 x) = 1

What is the general solution for 8tan(b)+12=3tan(b)+7 ?
The general solution for 8tan(b)+12=3tan(b)+7 is b=(3pi)/4+pin