What is the general solution for (tan(x)+1)(sec(x)-2)=0 ?

The general solution for (tan(x)+1)(sec(x)-2)=0 is x=(3pi)/4+pin,x= pi/3+2pin,x=(5pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(tan(x)+1)(sec(x)-2)=0

(tan (x) + 1) (sec (x) - 2) = 0

x = \frac{3 π}{4} + πn, x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

(tan (x) + 1) (sec (x) - 2) = 0

Solving each part separately

tan (x) + 1 = 0 or sec (x) - 2 = 0

tan (x) + 1 = 0 : x = \frac{3 π}{4} + πn

sec (x) - 2 = 0 : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Combine all the solutions

x = \frac{3 π}{4} + πn, x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

cot^{2} (x) = cot (x)

- sin (x) - 1 = 0

y, x = sec (\frac{1}{y})

sin (x) = \frac{7}{10}

sin (x) = \frac{7}{11}

What is the general solution for (tan(x)+1)(sec(x)-2)=0 ?
The general solution for (tan(x)+1)(sec(x)-2)=0 is x=(3pi)/4+pin,x= pi/3+2pin,x=(5pi)/3+2pin