What is the general solution for cos(θ)=sqrt(1/2) ?

The general solution for cos(θ)=sqrt(1/2) is θ=0.78539…+2pin,θ=2pi-0.78539…+2pin

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cos(θ)=sqrt(1/2)

cos (θ) = \frac{1}{2}

θ = 0.78539 \dots + 2 πn, θ = 2 π - 0.78539 \dots + 2 πn

Degrees

θ = 4 5^{\circ} + 36 0^{\circ} n, θ = 31 5^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{1}{2}

Apply trig inverse properties

cos (θ) = \frac{1}{2}

General solutions for

cos (θ) = \frac{1}{2}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{1}{2}) + 2 πn, θ = 2 π - arccos (\frac{1}{2}) + 2 πn

θ = arccos (\frac{1}{2}) + 2 πn, θ = 2 π - arccos (\frac{1}{2}) + 2 πn

Show solutions in decimal form

θ = 0.78539 \dots + 2 πn, θ = 2 π - 0.78539 \dots + 2 πn

cos (3 x) = sin (3 x)

sin (t) = \frac{3}{5}

cos (2 x) + 5 cos (x) = 2

cos (5 x) = 1

cos (θ) = 0.52

What is the general solution for cos(θ)=sqrt(1/2) ?
The general solution for cos(θ)=sqrt(1/2) is θ=0.78539…+2pin,θ=2pi-0.78539…+2pin