What is the general solution for cos(θ)=-c ?

The general solution for cos(θ)=-c is θ=arccos(-c)+2pin,θ=-arccos(-c)+2pin

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cos(θ)=-c

cos (θ) = - c

θ = arccos (- c) + 2 πn, θ = - arccos (- c) + 2 πn

Solution steps

cos (θ) = - c

Apply trig inverse properties

θ = arccos (- c) + 2 πn, θ = - arccos (- c) + 2 πn

sin (t) = 1

(tan (x) - 1) (3 tan (x) - 1) = 0

\frac{1 - cos ( 2 x )}{sin ( 2 x )} = 3

2 sin (- 3 x - \frac{π}{4}) = 2, 0 \leq x \leq 2 π

9 sin^{2} (θ) - 9 sin (θ) - 2 = - 6 sin (θ)

What is the general solution for cos(θ)=-c ?
The general solution for cos(θ)=-c is θ=arccos(-c)+2pin,θ=-arccos(-c)+2pin