What is the general solution for tan(θ)= 1/(-sqrt(3)) ?

The general solution for tan(θ)= 1/(-sqrt(3)) is θ=(5pi)/6+pin

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tan(θ)= 1/(-sqrt(3))

tan (θ) = \frac{1}{- 3}

θ = \frac{5 π}{6} + πn

Solution steps

tan (θ) = \frac{1}{- 3}

Simplify

\frac{1}{- 3} : - \frac{3}{3}

General solutions for

tan (θ) = - \frac{3}{3}

θ = \frac{5 π}{6} + πn

sin^{2} (θ) - cos^{2} (θ) = sin (θ)

4 sin (c) + 3 = sin (c) + 1

(tan (x) + 1) (3 tan (x) - 1) = 0

tan^{2} (x) sin (x) - sin (x) = 0

2 cos^{2} (t) - 3 cos (t) + 1 = 0

What is the general solution for tan(θ)= 1/(-sqrt(3)) ?
The general solution for tan(θ)= 1/(-sqrt(3)) is θ=(5pi)/6+pin