What is the general solution for 2=2-2sin(θ) ?

The general solution for 2=2-2sin(θ) is θ=2pin,θ=pi+2pin

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2=2-2sin(θ)

2 = 2 - 2 sin (θ)

θ = 2 πn, θ = π + 2 πn

Solution steps

2 = 2 - 2 sin (θ)

Switch sides

2 - 2 sin (θ) = 2

Subtract

2

from both sides

2 - 2 sin (θ) - 2 = 2 - 2

Simplify

- 2 sin (θ) = 0

Divide both sides by

- 2

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

sin (2 θ) - 3 cos (θ) = 0

- sin^{2} (x) + cos^{2} (x) = 0

sin (θ) - cos (2 θ) = 0

sec (θ) = - \frac{5}{3}

3 sin (x) = 2 cos (x)

What is the general solution for 2=2-2sin(θ) ?
The general solution for 2=2-2sin(θ) is θ=2pin,θ=pi+2pin