What is the general solution for sqrt(3)sec(2x)-2=0 ?

The general solution for sqrt(3)sec(2x)-2=0 is x= pi/(12)+pin,x=(11pi)/(12)+pin

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sqrt(3)sec(2x)-2=0

3 sec (2 x) - 2 = 0

x = \frac{π}{12} + πn, x = \frac{11 π}{12} + πn

Solution steps

3 sec (2 x) - 2 = 0

Move

2

to the right side

3 sec (2 x) = 2

Divide both sides by

3

sec (2 x) = \frac{2 3}{3}

General solutions for

sec (2 x) = \frac{2 3}{3}

2 x = \frac{π}{6} + 2 πn, 2 x = \frac{11 π}{6} + 2 πn

Solve

2 x = \frac{π}{6} + 2 πn : x = \frac{π}{12} + πn

Solve

2 x = \frac{11 π}{6} + 2 πn : x = \frac{11 π}{12} + πn

x = \frac{π}{12} + πn, x = \frac{11 π}{12} + πn

2 sin^{2} (θ) + 3 sin (θ) = 0

sin (x + \frac{π}{6}) + sin (x - \frac{π}{6}) = - \frac{3}{2}

3 csc (\frac{2 x}{3}) - 2 = 0

cos (θ) = \frac{8}{10}

5 sin (a) + 3 = sin (a) + 2

What is the general solution for sqrt(3)sec(2x)-2=0 ?
The general solution for sqrt(3)sec(2x)-2=0 is x= pi/(12)+pin,x=(11pi)/(12)+pin