What is the general solution for cos(sqrt(2)T)=1,0<= T<= 2pi ?

The general solution for cos(sqrt(2)T)=1,0<= T<= 2pi is T=0,T=sqrt(2)pi

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cos(sqrt(2)T)=1,0<= T<= 2pi

cos (2 T) = 1, 0 \leq T \leq 2 π

T = 0, T = 2 π

Solution steps

cos (2 T) = 1, 0 \leq T \leq 2 π

General solutions for

cos (2 T) = 1

2 T = 0 + 2 πn

Solve

2 T = 0 + 2 πn : T = 2 πn

T = 2 πn

Solutions for the range

0 \leq T \leq 2 π

T = 0, T = 2 π

2 - 2 cos^{2} (\frac{x}{2}) = 2 cos^{2} (x)

sec^{2} (θ) - 2 = tan^{2} (θ)

cos (x) = sin (x) + 1

2 sin^{2} (θ) = 3 (1 - cos (- θ))

sec (x) - 2 = 0

What is the general solution for cos(sqrt(2)T)=1,0<= T<= 2pi ?
The general solution for cos(sqrt(2)T)=1,0<= T<= 2pi is T=0,T=sqrt(2)pi