What is the general solution for sqrt(2)cos(2θ)=-1 ?

The general solution for sqrt(2)cos(2θ)=-1 is θ=(3pi)/8+pin,θ=(5pi)/8+pin

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sqrt(2)cos(2θ)=-1

2 cos (2 θ) = - 1

θ = \frac{3 π}{8} + πn, θ = \frac{5 π}{8} + πn

Solution steps

2 cos (2 θ) = - 1

Divide both sides by

2

cos (2 θ) = - \frac{2}{2}

General solutions for

cos (2 θ) = - \frac{2}{2}

2 θ = \frac{3 π}{4} + 2 πn, 2 θ = \frac{5 π}{4} + 2 πn

Solve

2 θ = \frac{3 π}{4} + 2 πn : θ = \frac{3 π}{8} + πn

Solve

2 θ = \frac{5 π}{4} + 2 πn : θ = \frac{5 π}{8} + πn

θ = \frac{3 π}{8} + πn, θ = \frac{5 π}{8} + πn

16 cos^{2} (x) = 12

sin (2 x) = 0.4

sin (x) = - 0.4

θ, 3 cos (θ) = 1 + cos (θ)

tan (a) = \frac{5}{12}, sin (a) < 0, sin (a) + cos (a)

What is the general solution for sqrt(2)cos(2θ)=-1 ?
The general solution for sqrt(2)cos(2θ)=-1 is θ=(3pi)/8+pin,θ=(5pi)/8+pin