What is the general solution for -3arcsin(2x)=pi ?

The general solution for -3arcsin(2x)=pi is x=-(sqrt(3))/4

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-3arcsin(2x)=pi

- 3 arcsin (2 x) = π

x = - \frac{3}{4}

Solution steps

- 3 arcsin (2 x) = π

Divide both sides by

- 3

arcsin (2 x) = - \frac{π}{3}

Apply trig inverse properties

2 x = - \frac{3}{2}

Solve

2 x = - \frac{3}{2} : x = - \frac{3}{4}

x = - \frac{3}{4}

3 tan (3 x) = 3

\frac{1}{2} + cos (θ) = 0

(2 cos (x) - 1) (2 sin (x) + 3) = 0

2 sin (2 x) = 2 cos (x)

tan (\frac{1}{2} x) + 1 = 0

What is the general solution for -3arcsin(2x)=pi ?
The general solution for -3arcsin(2x)=pi is x=-(sqrt(3))/4