What is the general solution for 2cos(x)sin(x)-sin(x)=0 ?

The general solution for 2cos(x)sin(x)-sin(x)=0 is x=2pin,x=pi+2pin,x= pi/3+2pin,x=(5pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos(x)sin(x)-sin(x)=0

2 cos (x) sin (x) - sin (x) = 0

x = 2 πn, x = π + 2 πn, x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

2 cos (x) sin (x) - sin (x) = 0

Factor

2 cos (x) sin (x) - sin (x) : sin (x) (2 cos (x) - 1)

sin (x) (2 cos (x) - 1) = 0

Solving each part separately

sin (x) = 0 or 2 cos (x) - 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

2 cos (x) - 1 = 0 : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

sin (4 x) + 1 = cos (4 x)

tan (x) = \frac{36}{28}

tan (x) = - 2 sin (x)

2 cos (θ) = 1

cos (x) = sin (4 x)

What is the general solution for 2cos(x)sin(x)-sin(x)=0 ?
The general solution for 2cos(x)sin(x)-sin(x)=0 is x=2pin,x=pi+2pin,x= pi/3+2pin,x=(5pi)/3+2pin