What is the general solution for sqrt(2)cos(θ)=1 ?

The general solution for sqrt(2)cos(θ)=1 is θ= pi/4+2pin,θ=(7pi)/4+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sqrt(2)cos(θ)=1

2 cos (θ) = 1

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Solution steps

2 cos (θ) = 1

Divide both sides by

2

cos (θ) = \frac{2}{2}

General solutions for

cos (θ) = \frac{2}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

cos (x) = sin (4 x)

0 = 2 + 4 sin (x)

sin (x) = \frac{1}{5}

cos (x) + cos (x) tan (x) = 0

4 sin^{3} (x) - sin (x) = 0

What is the general solution for sqrt(2)cos(θ)=1 ?
The general solution for sqrt(2)cos(θ)=1 is θ= pi/4+2pin,θ=(7pi)/4+2pin