What is the general solution for -2sin(b)-6=sin(b)-3 ?

The general solution for -2sin(b)-6=sin(b)-3 is b=(3pi)/2+2pin

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-2sin(b)-6=sin(b)-3

- 2 sin (b) - 6 = sin (b) - 3

b = \frac{3 π}{2} + 2 πn

Solution steps

- 2 sin (b) - 6 = sin (b) - 3

Solve by substitution

sin (b) = - 1

sin (b) = - 1 : b = \frac{3 π}{2} + 2 πn

Combine all the solutions

b = \frac{3 π}{2} + 2 πn

cos (t) = - sin (t)

cos (4 x) \cdot 4 = 0

cos^{2} (x) = \frac{3}{2}

sin (\frac{x}{2}) = \frac{3}{5}

16 cos^{2} (x) - 8 = 0

What is the general solution for -2sin(b)-6=sin(b)-3 ?
The general solution for -2sin(b)-6=sin(b)-3 is b=(3pi)/2+2pin