What is the general solution for 2cos^2(x)+cos(x)-3=0 ?

The general solution for 2cos^2(x)+cos(x)-3=0 is x=2pin

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2cos^2(x)+cos(x)-3=0

2 cos^{2} (x) + cos (x) - 3 = 0

x = 2 πn

Solution steps

2 cos^{2} (x) + cos (x) - 3 = 0

Solve by substitution

cos (x) = 1, cos (x) = - \frac{3}{2}

cos (x) = 1 : x = 2 πn

cos (x) = - \frac{3}{2} :

No Solution

Combine all the solutions

x = 2 πn

5 sin (θ) tan (θ) - 10 tan (θ) + 3 sin (θ) - 6 = 0

3 cos^{2} (θ) + 6 cos (θ) - 4 = 0

arccos (x) = 1

cos (x) = \frac{3}{4}

sin (x) = sin (\frac{x}{2})

What is the general solution for 2cos^2(x)+cos(x)-3=0 ?
The general solution for 2cos^2(x)+cos(x)-3=0 is x=2pin