What is the general solution for 7tan(A)+sqrt(42)=0 ?

The general solution for 7tan(A)+sqrt(42)=0 is A=-0.74689…+pin

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7tan(A)+sqrt(42)=0

7 tan (A) + 42 = 0

A = - 0.74689 \dots + πn

Solution steps

7 tan (A) + 42 = 0

Move

42

to the right side

7 tan (A) = - 42

Divide both sides by

7

tan (A) = - \frac{42}{7}

Apply trig inverse properties

A = arctan (- \frac{42}{7}) + πn

Show solutions in decimal form

A = - 0.74689 \dots + πn

2 sin (x + \frac{π}{4}) = 1

cos (3 x) = \frac{1}{2}

sin (x + \frac{π}{4}) = - \frac{2}{2}, 0 \leq x \leq 2 π

1 + 2 sin^{2} (x) = - 5 cos (x)

sec^{2} (x) tan^{2} (x) + 3 sec^{2} (x) - 2 tan^{2} (x) = 3

What is the general solution for 7tan(A)+sqrt(42)=0 ?
The general solution for 7tan(A)+sqrt(42)=0 is A=-0.74689…+pin