What is the general solution for sin(x+pi/4)=-(sqrt(2))/2 ,0<= x<= 2pi ?

The general solution for sin(x+pi/4)=-(sqrt(2))/2 ,0<= x<= 2pi is x=pi,x=(3pi)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(x+pi/4)=-(sqrt(2))/2 ,0<= x<= 2pi

sin (x + \frac{π}{4}) = - \frac{2}{2}, 0 \leq x \leq 2 π

x = π, x = \frac{3 π}{2}

Solution steps

sin (x + \frac{π}{4}) = - \frac{2}{2}, 0 \leq x \leq 2 π

General solutions for

sin (x + \frac{π}{4}) = - \frac{2}{2}

x + \frac{π}{4} = \frac{5 π}{4} + 2 πn, x + \frac{π}{4} = \frac{7 π}{4} + 2 πn

Solve

x + \frac{π}{4} = \frac{5 π}{4} + 2 πn : x = 2 πn + π

Solve

x + \frac{π}{4} = \frac{7 π}{4} + 2 πn : x = 2 πn + \frac{3 π}{2}

x = 2 πn + π, x = 2 πn + \frac{3 π}{2}

Solutions for the range

0 \leq x \leq 2 π

x = π, x = \frac{3 π}{2}

1 + 2 sin^{2} (x) = - 5 cos (x)

sec^{2} (x) tan^{2} (x) + 3 sec^{2} (x) - 2 tan^{2} (x) = 3

2 cos (x) - 3 = 0

cot (x) + 6 sin (x) - 2 cos (x) = 3

cos (2 θ) = cos^{2} (θ)

What is the general solution for sin(x+pi/4)=-(sqrt(2))/2 ,0<= x<= 2pi ?
The general solution for sin(x+pi/4)=-(sqrt(2))/2 ,0<= x<= 2pi is x=pi,x=(3pi)/2