What is the general solution for 0=2sin(x)-1 ?

The general solution for 0=2sin(x)-1 is x= pi/6+2pin,x=(5pi)/6+2pin

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0=2sin(x)-1

0 = 2 sin (x) - 1

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

0 = 2 sin (x) - 1

Switch sides

2 sin (x) - 1 = 0

Move

1

to the right side

2 sin (x) = 1

Divide both sides by

2

sin (x) = \frac{1}{2}

General solutions for

sin (x) = \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

t, x = cos (2 t)

- 9 sin^{2} (θ) - 3 cos (θ) + 2 = - 5

csc (x) = - 1 + cot (x)

2 sin (3 x) = 3

4 sin (3 θ) = 7 cos (3 θ), 0^{\circ} \leq 3 θ < 72 0^{\circ}

What is the general solution for 0=2sin(x)-1 ?
The general solution for 0=2sin(x)-1 is x= pi/6+2pin,x=(5pi)/6+2pin