What is the general solution for 8cos(B)+sqrt(52)=0 ?

The general solution for 8cos(B)+sqrt(52)=0 is B=2.69376…+2pin,B=-2.69376…+2pin

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8cos(B)+sqrt(52)=0

8 cos (B) + 52 = 0

B = 2.69376 \dots + 2 πn, B = - 2.69376 \dots + 2 πn

Solution steps

8 cos (B) + 52 = 0

52 = 213

8 cos (B) + 213 = 0

Move

213

to the right side

8 cos (B) = - 213

Divide both sides by

8

cos (B) = - \frac{13}{4}

Apply trig inverse properties

B = arccos (- \frac{13}{4}) + 2 πn, B = - arccos (- \frac{13}{4}) + 2 πn

Show solutions in decimal form

B = 2.69376 \dots + 2 πn, B = - 2.69376 \dots + 2 πn

sec (\frac{x}{2}) = 2

sin (5 x) = \frac{3}{2}

sin^{2} (θ) - cos^{2} (θ) = - 1

cos^{2} (x) - 4 cos (x) = 0

x, sin (x) + cot (x) cos (x) = \frac{1}{f}

What is the general solution for 8cos(B)+sqrt(52)=0 ?
The general solution for 8cos(B)+sqrt(52)=0 is B=2.69376…+2pin,B=-2.69376…+2pin