What is the general solution for sin^2(θ)-cos^2(θ)=-1 ?

The general solution for sin^2(θ)-cos^2(θ)=-1 is θ=pin

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sin^2(θ)-cos^2(θ)=-1

sin^{2} (θ) - cos^{2} (θ) = - 1

θ = πn

Solution steps

sin^{2} (θ) - cos^{2} (θ) = - 1

Rewrite using trig identities

- cos (2 θ) = - 1

Divide both sides by

- 1

cos (2 θ) = 1

General solutions for

cos (2 θ) = 1

2 θ = 0 + 2 πn

Solve

2 θ = 0 + 2 πn : θ = πn

θ = πn

cos^{2} (x) - 4 cos (x) = 0

x, sin (x) + cot (x) cos (x) = \frac{1}{f}

\frac{1}{sin ( x )} = 2

tan (x) csc (x) - 2 tan (x) = 0

1 - 2 sin (θ) = 0

What is the general solution for sin^2(θ)-cos^2(θ)=-1 ?
The general solution for sin^2(θ)-cos^2(θ)=-1 is θ=pin