What is the general solution for -10=8tan(x)+6 ?

The general solution for -10=8tan(x)+6 is x=-1.10714…+pin

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-10=8tan(x)+6

- 10 = 8 tan (x) + 6

x = - 1.10714 \dots + πn

Degrees

x = - 63.43494 \dots^{\circ} + 18 0^{\circ} n

Solution steps

- 10 = 8 tan (x) + 6

Switch sides

8 tan (x) + 6 = - 10

Move

6

to the right side

8 tan (x) + 6 = - 10

Subtract

6

from both sides

8 tan (x) + 6 - 6 = - 10 - 6

Simplify

8 tan (x) = - 16

8 tan (x) = - 16

Divide both sides by

8

8 tan (x) = - 16

Divide both sides by

8

\frac{8 tan ( x )}{8} = \frac{- 16}{8}

Simplify

\frac{8 tan ( x )}{8} = \frac{- 16}{8}

Simplify

\frac{8 tan ( x )}{8} : tan (x)

\frac{8 tan ( x )}{8}

Divide the numbers:

\frac{8}{8} = 1

= tan (x)

Simplify

\frac{- 16}{8} : - 2

\frac{- 16}{8}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{16}{8}

Divide the numbers:

\frac{16}{8} = 2

= - 2

tan (x) = - 2

tan (x) = - 2

tan (x) = - 2

Apply trig inverse properties

tan (x) = - 2

General solutions for

tan (x) = - 2

tan (x) = - a \Rightarrow x = arctan (- a) + πn

x = arctan (- 2) + πn

x = arctan (- 2) + πn

Show solutions in decimal form

x = - 1.10714 \dots + πn

- 4 sin (2 θ) = 5 cos (2 θ), 0^{\circ} \leq 2 θ < 72 0^{\circ}

2 cos (2 x) + cos (x) - 1 = 0

0.79 = sin (x)

1 + cot (x) = csc (x)

4 cos^{2} (x) - 42 cos (x) + 2 = 0

What is the general solution for -10=8tan(x)+6 ?
The general solution for -10=8tan(x)+6 is x=-1.10714…+pin