What is the general solution for csc(2x)+1=0 ?

The general solution for csc(2x)+1=0 is x=(3pi)/4+pin

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csc(2x)+1=0

csc (2 x) + 1 = 0

x = \frac{3 π}{4} + πn

Solution steps

csc (2 x) + 1 = 0

Move

1

to the right side

csc (2 x) = - 1

General solutions for

csc (2 x) = - 1

2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

cos (5 x) - cos (x) = sin (3 x)

1 = cos (\frac{( π ( t - 22 ) )}{183})

cot (x) = - csc^{2} (x)

3 cos^{2} (θ) + 4 cos (θ) - 4 = 0

sin (x) = - cos^{2} (x) - 1

What is the general solution for csc(2x)+1=0 ?
The general solution for csc(2x)+1=0 is x=(3pi)/4+pin