What is the general solution for tan(x)+1=0,0<= x<= 2pi ?

The general solution for tan(x)+1=0,0<= x<= 2pi is x=(3pi)/4 ,x=(7pi)/4

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tan(x)+1=0,0<= x<= 2pi

tan (x) + 1 = 0, 0 \leq x \leq 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

Solution steps

tan (x) + 1 = 0, 0 \leq x \leq 2 π

Move

1

to the right side

tan (x) = - 1

General solutions for

tan (x) = - 1

x = \frac{3 π}{4} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

8 sin^{2} (θ) + 10 sin (θ) - 2 = 4 sin (θ) - 3

tan (x) = - \frac{5}{2}

5 sin^{2} (θ) - 4 cos (θ) - 9 = - cos (θ) - 6

sin (x) + 3 = - sin (x)

2 = cos (x)

What is the general solution for tan(x)+1=0,0<= x<= 2pi ?
The general solution for tan(x)+1=0,0<= x<= 2pi is x=(3pi)/4 ,x=(7pi)/4