What is the general solution for cos(x)=sin(15) ?

The general solution for cos(x)=sin(15) is x=1.30899…+360n,x=360-1.30899…+360n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(x)=sin(15)

cos (x) = sin (1 5^{\circ})

x = 1.30899 \dots + 36 0^{\circ} n, x = 36 0^{\circ} - 1.30899 \dots + 36 0^{\circ} n

Solution steps

cos (x) = sin (1 5^{\circ})

sin (1 5^{\circ}) = \frac{6 - 2}{4}

cos (x) = \frac{6 - 2}{4}

Apply trig inverse properties

x = arccos (\frac{6 - 2}{4}) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (\frac{6 - 2}{4}) + 36 0^{\circ} n

Show solutions in decimal form

x = 1.30899 \dots + 36 0^{\circ} n, x = 36 0^{\circ} - 1.30899 \dots + 36 0^{\circ} n

3 = 3 tan (x)

2 cot (x) + 1 = - 1

sin (θ) = \frac{3}{5}, cos (θ)

cos (2 θ) + 2 cos^{2} (θ) = 0

csc^{2} (t) = 3

What is the general solution for cos(x)=sin(15) ?
The general solution for cos(x)=sin(15) is x=1.30899…+360n,x=360-1.30899…+360n