What is the general solution for tan(θ)(1+tan^2(θ))=0 ?

The general solution for tan(θ)(1+tan^2(θ))=0 is θ=pin

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tan(θ)(1+tan^2(θ))=0

tan (θ) (1 + tan^{2} (θ)) = 0

θ = πn

Solution steps

tan (θ) (1 + tan^{2} (θ)) = 0

Solving each part separately

tan (θ) = 0 or 1 + tan^{2} (θ) = 0

tan (θ) = 0 : θ = πn

1 + tan^{2} (θ) = 0 :

No Solution

Combine all the solutions

θ = πn

tan (x) = 9

sin (2 x) = 0, 0 \leq x \leq 2 π

\frac{1}{2} = sin^{2} (x)

- 12 sin^{2} (θ) + 3 = 0

2 cot^{2} (x) - 4 = 2

What is the general solution for tan(θ)(1+tan^2(θ))=0 ?
The general solution for tan(θ)(1+tan^2(θ))=0 is θ=pin