What is the general solution for 4cos(θ)+5=0 ?

The general solution for 4cos(θ)+5=0 is No Solution for θ\in\mathbb{R}

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4cos(θ)+5=0

4 cos (θ) + 5 = 0

No Solution for θ \in R

Solution steps

4 cos (θ) + 5 = 0

Move

5

to the right side

4 cos (θ) + 5 = 0

Subtract

5

from both sides

4 cos (θ) + 5 - 5 = 0 - 5

Simplify

4 cos (θ) = - 5

4 cos (θ) = - 5

Divide both sides by

4

4 cos (θ) = - 5

Divide both sides by

4

\frac{4 cos ( θ )}{4} = \frac{- 5}{4}

Simplify

cos (θ) = - \frac{5}{4}

cos (θ) = - \frac{5}{4}

- 1 \leq cos (x) \leq 1

No Solution for θ \in R

cos (θ) = \frac{60}{78}

18 sin^{2} (x) = 9

x, sin (x) = cos (y)

2 - 2 sin^{2} (\frac{x}{2}) = 2 cos^{2} (x)

2 cos (x) + 2 sin (x) = 6

What is the general solution for 4cos(θ)+5=0 ?
The general solution for 4cos(θ)+5=0 is No Solution for θ\in\mathbb{R}