What is the general solution for cos(θ)=-0.5 ?

The general solution for cos(θ)=-0.5 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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cos(θ)=-0.5

cos (θ) = - 0.5

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Degrees

θ = 12 0^{\circ} + 36 0^{\circ} n, θ = 24 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = - 0.5

General solutions for

cos (θ) = - 0.5

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

sec (x) = \frac{5}{3}

x, y = \frac{sec ( x )}{cos ^{1} ( x )} + 8 y^{2}

3 cot^{2} (θ) - 4 csc (θ) = 1

sin (2 x) sin (x) = 0

4 - sin (θ) = cos (2 θ)

What is the general solution for cos(θ)=-0.5 ?
The general solution for cos(θ)=-0.5 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin