What is the general solution for sin(2x)sin(x)=0 ?

The general solution for sin(2x)sin(x)=0 is x=pin,x= pi/2+pin

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sin(2x)sin(x)=0

sin (2 x) sin (x) = 0

x = πn, x = \frac{π}{2} + πn

Solution steps

sin (2 x) sin (x) = 0

Solving each part separately

sin (2 x) = 0 or sin (x) = 0

sin (2 x) = 0 : x = πn, x = \frac{π}{2} + πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = πn, x = \frac{π}{2} + πn, x = 2 πn, x = π + 2 πn

Merge Overlapping Intervals

x = πn, x = \frac{π}{2} + πn

4 - sin (θ) = cos (2 θ)

sin (θ) = - 0.3

sin (x) = \frac{1}{1.52}

2 cos (x) + 2 = sin^{2} (x)

3 cot (\frac{1}{3} x) = 1

What is the general solution for sin(2x)sin(x)=0 ?
The general solution for sin(2x)sin(x)=0 is x=pin,x= pi/2+pin