What is the general solution for sin(x)= 1/(1.52) ?

The general solution for sin(x)= 1/(1.52) is x=0.71801…+2pin,x=pi-0.71801…+2pin

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sin(x)= 1/(1.52)

sin (x) = \frac{1}{1.52}

x = 0.71801 \dots + 2 πn, x = π - 0.71801 \dots + 2 πn

Solution steps

sin (x) = \frac{1}{1.52}

Apply trig inverse properties

x = arcsin (\frac{1}{1.52}) + 2 πn, x = π - arcsin (\frac{1}{1.52}) + 2 πn

Show solutions in decimal form

x = 0.71801 \dots + 2 πn, x = π - 0.71801 \dots + 2 πn

2 cos (x) + 2 = sin^{2} (x)

3 cot (\frac{1}{3} x) = 1

sin (x) = tan (\frac{x}{2})

2 sin^{2} (x) - 17 sin (x) + 8 = 0

4 cos^{2} (t) sin (t) - 2 cos (t) sin (t) = 0

What is the general solution for sin(x)= 1/(1.52) ?
The general solution for sin(x)= 1/(1.52) is x=0.71801…+2pin,x=pi-0.71801…+2pin