What is the general solution for -6cos(θ)-10=-7 ?

The general solution for -6cos(θ)-10=-7 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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-6cos(θ)-10=-7

- 6 cos (θ) - 10 = - 7

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

- 6 cos (θ) - 10 = - 7

Move

10

to the right side

- 6 cos (θ) = 3

Divide both sides by

- 6

cos (θ) = - \frac{1}{2}

General solutions for

cos (θ) = - \frac{1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

sin^{2} (x) = cos^{2} (x) + 1

tanh (x) = 1

tan (θ) = \frac{1}{3}

sin (θ) = \frac{20}{29}

2 cos (\frac{1}{2} x) - 3 = 0

What is the general solution for -6cos(θ)-10=-7 ?
The general solution for -6cos(θ)-10=-7 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin